Object is released and free-falling. Time taken to fall vertically from P to Q?

Keep in mind that you can utilize the two main concepts of a speed-time graph.

• As object is under free-fall, the acceleration (the gradient of the graph) is 10 m/s2.

• The area undereath the speed-time graph is the distance. So the area under the graph from P to Q is 120 m.

With this two equation, you can solve all unknowns.

Solutions: Option A

Converging Lens – Which ray is correct after passing through the lens

Which of the following light rays behaves correctly when it passes through the converging lens?

Solutions: Option C

Recall these basic concepts on the 3 rays

Energy - Ratio of KE to GPE at 10m when an object is released from 50m

Ans: Option C