**Solutions: Option B**

As **lamp X is thicker and shorter**, these two factors make the **resistance of X lower than Y**.

*Recall: Length increases, R increases & cross-sectional area increases, R decreases.*

*[R = pL/A]*

As both bulbs are connected to the same mains, (assume 240V), the potential difference across the bulbs are 240 V.

**Brightness of the bulb depends on power**, P = IV or V2/R, since V is constant, I across X is higher due to lower R,hence **power of X is greater than power of Y, hence X is brighter**.

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